for a = 1 The value of
x² + 2x -p is 0. find
the value of p
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hope it helps you my friend
Step-by-step explanation:
If the sum of the square of the roots of the equation x²+2x-p=0 is 8, what is the value of p?
P(x)=x²+2x-p
This is in the form ax²+bx+c.
So a=1,b=2,c=-p
Now, let the zeroes be a and b (u can take alpha and beta).
Given, a²+b²=8
(a+b)² - 2ab = 8
Now , Sum of roots = a+b= -b/a = -2
Product of roots = ab = c/a = -p
So, by putting the values we get,
(-2)² - 2(-p) = 8
4+2p=8
2p=8–4
p=4/2
p=2.
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