Question

For a 16.8 V h2o2 solution(d= 0.951g/ml). Calculate the molar fraction and ppm

Answer 1

Molar strength of H2O2 = 11.2 * Molarity

16.8 = 11.2 * M

M = 16.8/11.2 = 1.5 molar

Here we get,

n(solute) = 1 .5 moles

m(solute) = 1.5 *(molar mass of H2O2 = 34)= 51 g

V(solution) = 1000 ml

d(solution) = 0.951 g/ml

m(solution) = V *d = 951 g

m(solvent) = m (solution) - m (solute) = 951 - 51 = 900g

n(solvent) = 900/18 = 50

1) Calculation of mole fraction

Xsolute = n(solute) /n(solvent) + n(solute)

= 1.5 / 51.5 = 0.029

X solvent = 1 - Xsolute = 0.971

2) Calculation of ppm

= (51 g / 951 g) * 10^6

= 53627.76 ppm