Math, asked by kanikarathi123, 10 months ago

For a=2/3,b=-5/6 and c=1/2 ,prove that a×(b+c)=a×b+a×c​

Answers

Answered by yashica62
28

Step-by-step explanation:

a =  \frac{2}{3}  \:  \:  \: b =  \frac{ - 5}{6}  \:  \:  \: c =  \frac{1}{2}

a \times (b + c) = a  \times b + a \times c

a \times (b + c) = a \times (b + c)

 \frac{2}{3} ( \frac{ - 5}{6 }  +  \frac{1}{2} ) =  \frac{2}{3} ( \frac{ - 5}{6}  +  \frac{1}{2} )

 \frac{2}{3} ( \frac{ - 5 + 3}{6} ) =  \frac{2}{3} ( \frac{ - 5 + 3}{6} )

 \frac{2}{3} (  \frac{ - 2}{6} ) =  \frac{2}{3} (  \frac{ - 2}{6} )

 \frac{ - 2}{9}  =  \frac{ - 2}{9}

L. h. S. = R. H.S

may be I helpful....

plz follow me....

Answered by preetinegi779
0

a= b= - c= ½

  • a×(b+c) = a×b+a×c
  • ×(-+½) = ×-+×½
  • -10/18 + 2/6. = -10/18 + 2/6
  • -10+2/18. = -10+2/18
  • -8/18. = -8/18
  • -4/9. = -4/9
Similar questions