For a= 3 and b=4 verify the identities ( a+ b) square = a square+ 2 ab + b square and a square - b square = (a+ b ) .( a- b ) .
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a=3 and b=4
(a+b) ^2=a^2 + 2ab +b^2
(3+4) ^2=3^2+2(3) (4) +4^2
7^2=9+24+16
49=49 therefore, LHS=RHS
a^2-b^2=(a+b) (a-b)
3^2-4^2=(3+4) (3-4)
9-16=7(-1)
-7=-7
7=7
Therefore,LHS=RHS
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