Math, asked by aazammughal76, 2 months ago

For a 90° triangular open channel, depth of critical flow is 0.3m. The velocity of critical flow is?​

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Answered by rashidkhna73
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Answer:

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Answered by Anonymous
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Normal depth is the depth of flow that would occur if the flow was uniform and steady, and is usually predicted using the Manning's Equation. Critical depth is defined as the depth of flow where energy is at a minimum for a particular discharge. Flow profiles are classified by the slope of the channel (So), yn, and yc.

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