For a A.P, if (m+n) th term is p and (m−n) th term is q, then m th term is
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Step-by-step explanation:
let 1st term = a
and common difference = d
(m+n) th term is p
=> a + (m+n-1)d = p
=> a = p - (m+n-1)d ----(1)
(m-n) th term is p
=> a + (m-n-1)d = q
=> p - (m+n-1)d + (m-n-1)d = q [putting a from (1)]
=> (-m-n+1+m-n-1)d = q-p
=> -2nd = q-p
=> d = (p-q)/2n
putting d in (1),
a = p - (m+n-1)d = p - (m+n-1)(p-q)/2n
mth term
= a + (m-1)d
= p - (m+n-1)(p-q)/2n + (m-1)(p-q)/2n
= p + (-m-n+1+m-1)(p-q)/2n
= p - n(p-q)/2n
= p - (p-q)/2
= (2p - p + q)/2
= (p+q)/2
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