Physics, asked by TbiaSamishta, 11 months ago

For a analogue signal with bandwidth 8 khz, the nyquist sampling rate will be

Answers

Answered by aqibkincsem
2

"According to the nyquist theorem for analogue signal with 8khz bandwidth, the sampling rate must be double or more than double the bandwidth of signal.

In the question given, we have the following values

Bandwidth = 8 khz

Sampling Rate = 2 * Bandwidth

Sampling Rate = 2 * 8 khz

Sampling Rate = 16 khz

"

Answered by jaswasri2006
1

Sampling Rate = 2*(Bandwidth) = 2*8 = 16 kHz

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