Question

For a,b,c €r prove that (a-b)^2+(b-c)^2+(c-a)^2>=0

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

(a - b)2 + (b - c)2 = 0

(a - b)2 = -(b - c)2

But (a - b)2 ≥ 0 and (b - c)2 ≥ 0

Then (a - b)2 = 0 and (b - c)2 = 0

Therefore, a = b, and b = c.

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