Physics, asked by bldgsydinsp2292, 11 months ago

For a beam of rectangular section of width b and depth d, the maximum bending stress in the cross section for a moment m is

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Answered by bhoomikalokesh13
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For a rectangular beam with cross section having width b and depth d and loaded as shown in the diagram , Choose the ratio of maximum shear stress to maximum bending stress

A) b/2a

B) d/4a

C) b/4a

D) d/2a

The ratio of maximum shear stress to maximum bending stress is B)d/4a.

Formula for stress of a beam for rectangular section is

 \tau =  \frac{3}{2}  \times   \frac{ v_{max}}{a}

and formula for bending stress is

 \sigma =  \frac{m}{z}

Where

 v_{max} = maximum \: sheer \: force

z = section module.

m = maximum bending moment.

assume maximum shear force as p

so,

v_{max} = p

and hence the maximum shear stress will be

 \tau =  \frac{3}{2}  \times  \frac{p}{bd}

____consider the above as (A)

assume bending moment as pa

so,

 \sigma =  \frac{pa}{\frac{ {bd}^{2} }{6} } =  \frac{6pa}{ {bd}^{2} }

____consider the above as (B)

And from both (A) and (B)

the ratio of maximum shear stress to the maximum bending stress is

 \frac{ \tau}{  \sigma}  =  \frac{ \frac{3}{2}  \times  \frac{p}{bd} }{ \frac{6pa}{ {bd}^{2} } }

and therefore

 \frac{ \tau}{ \sigma}  =  \frac{d}{4a}

The ratio of maximum shear stress to maximum bending stress is d/4a.

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