For a biconvex lens, as shown in Fig. 1, calculate the image distance l’.
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Answer
(A)-p , r (B) -r,s (C) -p (D) -r,s
Solution
(A) when object is at focus , image is also real from equi- biconvex lens. <br>
<br> For equi biconvex
<br> Hence final image position v decreases <br> hence
also decrease <br> (B) From (i) R
<br> Radius of curvature increases i.e., now the object is not placed at focus and it is case when object is between focus and optical centre. Hence image formation is virtual. <br> (C) Glass slab provides shift of the object in the incident ray direction. so for lens object position becomes between focus and optical centre. <br> (D) When medium is changed then relative.
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