For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is ............times the magnitude of its instantaneous acceleration.
a) 2/pie
b) pie/2
c) pie
d) 2
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Hii friend,
The time period for revolution is,
T=2π/omega
when omega= constant (:-1)
T=2π
Since it is half rotation,
T/2=2π/2
T=π.
The answer is option (c).
Hope this helps you a little!!
The time period for revolution is,
T=2π/omega
when omega= constant (:-1)
T=2π
Since it is half rotation,
T/2=2π/2
T=π.
The answer is option (c).
Hope this helps you a little!!
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