Question

For a body in S.H.M. the velocity is given by the
relation V = V144-16x² ms! The maximum aè-
celeration is
a) 12 m/s2
b) 16m/s2
c) 36m/s2
d) 48m/s2​

Answer 1

Answer:

velocity of the particle in SHM, 

v=144−16x2=49−x2 

comparing with v=A2−x2

 we get A=3m w=4rad/s

 so, maximum acceleration, 

amax=Aw2 

          =3×42 

⇒amax=48m/s2