Question

For a body in S.H.M the velocity is given
by the relation
V = 64 – 4x2 m/ sec. The
maximum acceleration is
(A) 12 m/sec
(B) 16 m/sec
2
(C) 36 m/sec
(D) 48 m/sec2​

Answer 1

Explanation:

velocity of the particle in SHM,

v=

144−16x

2

=4

9−x

2

comparing with v=

A

2

−x

2

we get A=3m w=4rad/s

so, maximum acceleration,

a

max

=Aw

2

=3×4

2

⇒a

max

=48m/s

2