Question

For a body moving with uniform acceleration
'a' initial and final velocities in a time interval 't'
are 'u' and 'V' respectively. Then its average velocity in the time interval 't' is​

Answer 1

Answer:

The answer might be.....(v+u)/2

Explanation:

We know that,

Average velocity=Total displacement/total time taken...................(i)

Also, 3rd eq.of motion is...

v^2-u^2=2aS..

So,further solving it we get....

v^2-u^2=2aS

S=(v-u)(v+u)/2a

But, we know (v-u)/t=a

therefore S=(v+u)t/2...................(ii)

Substituting value of S from (ii) in (i), we get....

A.V.=S/t

A.V.=(v+u)t/2t

A.V.=(v+u)/2..........ANSWER

HOPE IT'S USEFUL......