Question

For a body moving with uniform acceleration'a', initial and final velocities in a time interval't' are 'u' and 'v' respectively.Then,it's average velocity in the time interval't' is
a) (v+at)
b) (v-at/2)
c) (v-at)
d) (u-at/2)​

Answer 1

Answer:

B

Explanation:

Average Velocity = Distance/time

Distance = ut + at^2/2

=> Distance/time = u+at/2        (i)

V = u + at

=> v-at/2 = u+at-at/2

=> u + at/2                                 (i)

Therefore V-at/2