Question

For a body of Mass ‘m’ moving in a circle of radius ‘r’ if its velocity is halved,
what will be the effect on the value of centripetal force?

Answer 1

Given,

Mass of the body = m

The radius of the body = r

To Find,

The centripetal force if the value of velocity is halved.

Solution,

The formula for calculating the centripetal force is

F = mv²/r -----(i)

Now,

It is given that the value of velocity is halved

So,

F new = m(1/2v)²/r

F new = 1/4 (mv²/r)

Substituting the value from equation (i)

F new = 1/4 F

Hence, the force becomes 1/4 times the original force.

Answer 2

Answer:

The effect of centripetal force is

Explanation:

Given:

Mass =m

Radius = r

Velocity ,v = $\frac{1}{2}$

To find:

Effect of centripetal force

Calculations:

Centripetal force: It is defined as the force which makes a body followed by a circular path is known as centripetal force.

$F=\frac{mv^{2} }{2}$

mass = m

Velocity, v =$\frac{1}{2}$

Putting this values we get;

$F=\frac{m(\frac{1}{2}) ^{2} }{r} \\F=\frac{mv^{2} }{4r}$

Hence, The effect value of centripetal force is $F=\frac{mv^{2} }{4r}$

It is one fourth to the centripetal force.