Question

For a body that is dropped from a height,find the ratio of the velocities acquired at the end of 1 second,2 seconds and 3 seconds, respectively.​

Answer 1

the body acquires following velocities

v=u + gt

v is final velocity

u is initial velocity

g is gravitational acceleration

t is time

here u is always zero

so the velocities are

9.8m/s,19.6 m/s and 29.4 m/s respectively for 1,2and 3 seconds

Answer 2

Answer:1:2:3

Explanation:The velocity is given by the equation v=u+ at.

Since the body is dropped from a height, initial velocity is taken as 0.

Then, the equation will become just at.

That is the velocity is directly proportional to the time.

Therefore, velocity after 1 second is 9.8 m/s, after 2 seconds 19. 6 m/s and after 3 seconds 29.4 m/s.

Therefore the required ratio is 1:2:3.