For a body thrown upward time of ascending is 10 sec. Then, time of descending for it not neglecting the air friction be…….
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Answer:
When body is moving upward, time of ascent is given by:-
As we know that gravity is acting down-ward & so does the force due to air resistance, hence for total acceleration we can imply
a
total
=g+
m
R
{R: Resistive force due to air}
∴⇒t
a
=
(g+
m
R
)
v
----------1 {v:Initial velocity}
Now, for time period of body in descent the air resistive force is acting in upward direction because the gravity is acting in downward direction.
∴ for total acceleration in this case we get
a
total
=g−
m
R
⇒t
d
=
(g−
m
R
)
v
-----------2
From Statement 1 & 2, we get time of descent is greater.
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