Question

For a car moves at a regular speed , the ratio d/t ……………….. increases is constant Decreases Is doubled

Answer 1

Answer:

Stopping Distance:

s=  

2a

v  

2

−u  

2

 

s=  

2(  

m

−F  

)

0−u  

2

​

 

s=  

2F

mu  

2

 

​  

As m and F are constant  

s∝u  

2

 

s  

1

​

 

s  

2

​

 

​

=(  

u  

1

​

 

u  

2

​

 

​

)  

2

 

s  

1

​

 

s  

2

​

 

​

=(  

u

2u

​

)  

2

 

s  

2

​

=4s  

1

​

 

Stopping distance increases to 4times

Explanation: