Question

For a Carnot engine, the source is at 500 K and the sink at
300 K. What is efficiency of this engine :
(a) 0.2 (b) 0.4
(c) 0.6 (d) 0.3

Answer 1

For a Carnot engine, with the source at 500K and sink at 300K, the efficiency of the engine is 0.4

• we use formula to find the efficiency of the engine
• $n=\dfrac{T_1-T_2}{T_1}$
• Given
• $T_1=500K\\\\T_2=300K\\\\n=\dfrac{T_1-T_2}{T_1}\\\\=\dfrac{500-300}{500}\\\\=\dfrac{200}{500}\\\\=0.4$

Answer 2

The efficiency of the engine is n = 0.4

Option (B) is correct.

Explanation:

We are given that:

• T1 = 500 K
• T2 = 300 K
• n = efficiency of the engine = ?

Efficiency of the engine can be calculated by using the formula

n = T1 - T2 / T1

n = 500 K - 300 K / 500 K

n = 200 K / 500 K

n = 0.4

Thus the efficiency of the engine is n = 0.4

Also learn more

A perfect Carnot engine utilizes an ideal gas. The source temperature is 500 K and sink temperature is 375 K. If the engine takes 600 kcal per cycle from the source, then calculate a. The efficiency of the engine b. Work done per cycle c. Heat rejected to the sink per cycle  ?

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