Question

For a CE- transistor amplifier , the audio signal voltage across the collector resistance of 2 k Omega is 2 V . Suppose the current amplifiaction factor of the transistor is 100 . Find the input signal voltage and base current , if the base resistance is 1 k Omega .

Answer 1

Here is your answer:

0.01 V

Explanation:

Solution :

Here : v0=2V,β=100,

RC (collector resistance) =2kΩ,RB=1kΩ

As Av = v0/v1

          = β(RC/RB),

        vi=v0(RB/ RC) (1/β)

           =(2V) (1kΩ/2kΩ) (1/100)

            =0.01V .

Answer 2

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Answer:

d) 10mV

Explanation:

Voltage = Rc = 2 k = 2 × 10³

(Given)Base resistance = Rb = 1 k

(Given)Vo=2VInput voltage (Vi) = ?

Thus, using the equation

-B = Ic/lb = 100VolcRc2V

Ic=2/Rc = 2/2 × 103 Q= 10-3 A =1mA

Calculating the base current -

= lb = lc / B= 10-3/100= 10 × 10-6 A= 10

ΜΑInput resistance voltage

= Vi = Rb / lb= 1 x 103 x 10 x 10-6

= 10mV

Thus, the input signal voltage is 10mV,