Question

for a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2kohm is 2V. suppose the current amplification factor of the transistor is 100,find the input signal voltage and base current, if the base resistance is 1kohm​

Answer 1

Answer:

Given that:

I

β

I

α

=100;R

B

=1000Ω

⇒β=100=

I

β

I

α

⇒V

0

=4V

⇒

V

i

V

0

=β

R

B

R

L

⇒V

i

=

100×2000

4×1000

=0.02=20 mV

Answer 2

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Answer:

d) 10mV

Explanation:

Voltage = Rc = 2 k = 2 × 10³

(Given)Base resistance = Rb = 1 k

(Given)Vo=2VInput voltage (Vi) = ?

Thus, using the equation

-B = Ic/lb = 100VolcRc2V

Ic=2/Rc = 2/2 × 103 Q= 10-3 A =1mA

Calculating the base current -

= lb = lc / B= 10-3/100

= 10 × 10-6 A= 10 ΜΑ

input resistance voltage

= Vi = Rb / lb= 1 x 103 x 10 x 10-6

= 10mV

Thus, the input signal voltage is 10mV,