Question

For a cell of e.m.f. 2 V, a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2 ohm resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is *

2 points

(a) 1 ohm
(b) 0.5 ohm
(c) 1.2 ohm
(d) 2.5ohm

​

Answer 1

Answer:

r={(l

1

−l

2

)/l

2

}×R

l

1

=50cm

l

2

=40cm

R=2Ω

r=

40

50−40

×2

r=0.50

Explanation:

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