Question

For a certain machine VR is 125 to lift a load of 11.90KN an effort of 190 N is required to lift a load of 72 KN and identify the type of machine

Answer 1

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Answer 2

The effort required to lift a load of 72 KN by the machine is 1149.70 N and the machine is reversible

Given,

VR of the machine = 125

W of first load = 11.90 KN

P for first load = 190 N

W of second load = 72 KN

To Find,

P for the second load

Solution,

We can solve this problem using the following method:

$MA = \frac{W}{P}$

$MA = \frac{11.90 \times 10^3}{190}$

$MA = 62.63$

Now:

$\eta = \frac{MA}{VR} \times 100$

$\eta = \frac{62.63}{125} \times 100$

$\eta = 50.10 \hspace{0.1cm} \%$

Since η for the machine is greater than 50%, the machine is reversible

Now, the effort required to lift a load of 72 N:

$\eta = \frac{MA}{VR} \times 100$

$\eta = \frac{\frac{W}{P}}{VR} \times 100$

$\eta = \frac{W}{P \times VR} \times 100$

$P = \frac{W}{\eta \times VR} \times 100$

$P = \frac{72 \times 10^3}{125 \times 50.10} \times 100$

$P = 1149.70 N$

Therefore, the effort required to lift a load of 72 N by the machine is 1149.70 N

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