Question

for a certain normal distribution, the first moment about 10 is 40 and the fourth movement about about 50 is 48.what is the arithmetic mean and standard deviation of the distribution? ​

Answer 1

Step-by-step explanation:

Given For a certain normal distribution, the first moment about 10 is 40 and the fourth movement about about 50 is 48.what is the arithmetic mean and standard deviation of the distribution?  

• Mean is equal to A + μ
• Mean = 10 + 40
•         = 50
• About a point p = 50 is μ4 = 48
• Since mean is 50,  
• 3 σ^2 = μ4
• Or 3 σ^2 = 48
• Or σ^2 = 16
• Or σ = 4  
• So standard deviation is 4

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https://brainly.in/question/14180215