For a certain sum at particular rate the amount after 2 years is Rs 6,200 and afte 3 1/2 year is Rs 7,100 Find the ratio of interest
Answers
Step-by-step explanation:
Let A be the amount and R be the interest, compounding annual
A x ((100 + R)÷100)^ 2 = 6200
A x ((100+R)÷100)^3 = 7400
Now
2÷ 1,
(100 + R)÷100 = 7400÷6200
100 + R =( 74÷62. ) X 100
100 + R = 119.3548387097
R = 19.3548387097
To find Amount,
A x( 119.3548387097/100)^2 =6200.
A x 1.4245577523= 6200
A = 6200÷1.4245577523
4,352.2279037055
In case of simple interest.
Let us take the question as involving simple interest.
Let P be the principal and R as interest rate.
Now
P + (P x 2 x R/100) = 6200
P + (Px 3xR/100) = 7400
(2) - (1)
3PR/100 - 2PR/100 = 7400 - 6200= 1200.
PR/ 100 = 1200.
(2) + (1)
2P + 3PR/100 + 2PR/100 = 7400 + 6200 = 13600.
2P + 5PR /100 = 13600.
Substituting for PR /100 as 1200.
2P +( 5 × 1200) =13600.
2P = 13600 - 6000= 7600.
P = 3800.
we have,
PR/100 = 1200.
3800× R /100 = 1200
R = 1200÷38,
31.58.
Hence the principal is 3800 and interest rate is 31.58.
Answer:
The principal amount is Rs 3800 and the rate of interest is 31.57%
Given:
Given that A1 = 6200 and T1 = 2
A2 = 7400 and T2 = 3
To find:
We have to find the principle and rate of interest.
Solution:
We have to find the principle and rate of interest.
The formula is,
A= P+PRTA=P+PRT
Given that,
A1=Rs. 6200 and T1=2
A2=Rs. 7400 and T2=3
Substitute the values in formula
6200 = P+PR \times 26200=P+PR×2
P+2PR = 6200 --- (1)P+2PR=6200−−−(1)
7400 = P+PR \times 37400=P+PR×3
P+3PR = 7400 --- (2)P+3PR=7400−−−(2)
By solving equations 1 and 2
P+2PR = 6200P+2PR=6200
P+3PR = 7400P+3PR=7400
We get,
-PR = -1200−PR=−1200
PR = 1200 ----- (3)PR=1200−−−−−(3)
Substitute PR in equation 1
P+2 \times 1200 = 6200P+2×1200=6200
P = 6200-2400P=6200−2400
P = Rs \ 3800P=Rs 3800
Substitute P in equation 3
(3800) \times R=1200(3800)×R=1200
R= \frac {1200}{3800} \times 100R=
3800
1200
×100
R = 31.57 \%R=31.57%
Step-by-step explanation:
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