Question

For a charge =8tcube+6rsquare+4t+2 flowing through a surface, find the instantaneously current flowing through the surface at t=2 second

Answer 1

we know that

I = dq/dt

q ,charge =

$8t {}^{3} + 6t {}^{2} + 4t + 2$

now differentiate it with respect to time

then ,

$i = 24t {}^{2} + 12t + 4$

at t = 2 sec

$i = 96 + 24 + 4$

$i = 124 \:ampere$

I hope it helps you