For a charge Q1, the effect of charge Q2 on Q1 will be,
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Explanation:
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F1 = -F2 is the proper answer.
Coulomb's Law:
- It states that the pressure among charged particles could be without delay proportional to the fabrication from the amount of the two expenses.
- F ∝ QIQ2, Secondly, it's also inversely proportional to the rectangular of the gap among them, i.e., F ∝ l/r2.
- The pressure among expenses QI and Q2 are given via way of means of F = k× (q₁q₂/r²)/.in which k is the proportionality steady and is identical to nine x 109 Nm²/C²
Explanation: :
- For expenses QI and Q2 are separated as shown, the pressure on QI due to Q2 could be F = k× (Q₁Q₂/r²).
- As indicated, the course could be closer to the left, if each of the expenses is positive.
- Similarly, the pressure on Q2 due to Q could be F = k× (Q₁Q₂/r²). As indicated, the course could be closer to the proper, if each of the expenses is positive.
Observation:
- The significance of each of the forces is identical, i.e., IF₁ = IF₂|. The course of each of the forces is the contrary course.
We can finish the relation between Fl and F2 as F1 = -F2.
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