Chemistry, asked by stutyraghuwansh753, 1 year ago

For a chemical reaction the energy of activation is 80 kilo joule of frequency factor 4.0 into 10 to the power 10 what is the rate of constant 400k

Answers

Answered by Anonymous
1

Explanation:

Rate constant can be calculated from Arrhenius equation

k

=

A

×

e

E

a

R

T

Where,

k = Rate constant

A = Frequency factor

E

a

= Activation energy

R = Gas constant

T = Absolute Temperature

k

=

8.0

×

10

10

s

1

×

e

(

42.0 kJ/mol × 1000 J/kJ

8.314 J/(mol K) × 298 K

)

=

3.48

×

10

3

Answered by Anonymous
2

Rate constant can be calculated from Arrhenius equation

k

=

A

×

e

E

a

R

T

Where,

k = Rate constant

A = Frequency factor

E

a

= Activation energy

R = Gas constant

T = Absolute Temperature

k

=

8.0

×

10

10

s

1

×

e

(

42.0 kJ/mol × 1000 J/kJ

8.314 J/(mol K) × 298 K

)

=

3.48

×

10

3

Similar questions