For a chemical reaction Y, + 2Z →
→ Product,
rate controlling step is Y '+ 1/2 Z → Q. If the
concentration of Z is doubled, the rate of
reaction will
1) Remain the same
2) Become four times
3) Become 1.414 times
4) Become double
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Answer:
3) option
Explanation:
rate law depends on rate determining step
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