Question

for a circle with centre o two tangents PA and PB form an angle of 80 ° from external point p . find m triangle POA ​

Answer 1

Step-by-step explanation:

Answer:

Given: ∠APB=80

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As we know that sum of ∠APB+∠AOB=180

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(Using Property)

∠AOB=100

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Δ AOP ≃ ΔBOP by SSS congruency criteria.

AO=BO (Radius of circle)

PO=PO (common side of triangle)

AP=BP (tangents form an external point)

∠AOP=∠BOP (CPCT )

∠POA+∠POB=∠AOB=100

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∠POA=50

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Answer 2

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