Question

for a cirlce with centre O , two tangent PA and PB from an angle of 80° from an external point P, find​

Answer 1

Answer:

I answer is the 50

Step-by-step explanation:

→OA,OB are radii,

PA,PB are tangent

→∆PAO=90°,∆PBO=90°,∆BPA=80°

In quadrilateral OAPB,

→90°+90°+80°+∆AOB=360°

→960°-180°-80°=100°

But ∆POA=1/2∆AOB

→1/2×100=50°

=∆POA=50°