Question

For a class prism of refracting angle 600, the minimum angle of deviation D- is found to be 360 with a
maximum error of 1.050. When a beam of parallel light is incident on the prism, find the range of
experimental value of refractive index'p'. lt is known that the refractive index';-r'ofthe material of the prism
is given by
. 1 A+D^y srnl
-
J
Lt: 'r,-, ,' ' sin(A/2)

Answer 1

Answer:

l*da mera.. c*ut tera

tere b*ap kaa ch*ut teri maa kaa lu*d.. tu cha*ka

Answer 2

$\sf\huge\bold\pink{Answer:}$

Minimum deviation δ=2i−A

where A is prism angle A=60°

So δ=40°

we know 

δ=2i−A

40=2i−60

i=50°

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30°

now using the snell's law 

n(air) sini=n(glass) sinr

sin50=n(glass) sin30

n(glass)=1.53