Question

For a compound microscope of length L, the focal
length of objective and eye piece are f and for
respectively. If D = 25 cm then approximate
magnification for normal adjustment is
mo mome
LD
to
L+D
(2) Forte
L+D​

Answer 1

Answer:

total magnification of simple microscope for normal adjustment is given as

$M = \frac{L}{f_o}\frac{D}{f_e}$

Explanation:

As we know that magnification of compound microscope is given as

$M = m_o m_e$

here we know that magnification of objective lens is given as approx

$m_o = \frac{L}{f_o}$

now for normal adjustment we know that final image forms at infinite

so we have

$m_e = \frac{D}{f_e}$

now we have

$M = \frac{L}{f_o}\frac{D}{f_e}$

#Learn

Topic : compound microscope

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