Question

for a concave mirror f= 5cm ,4=10cm, as per sing convention rules ,which is correct ​

Answer 1

Answer:

Your question is not clear dear

Answer 2

Hey mate here's your question will be...

Problem: 

An object is placed at a distance 2 f from the pole of a convex mirror of focal length f . The linear magnification is:

Solution: 

 Here,u=−2f

Here,u=−2fv=?

Here,u=−2fv=?v1+u1=f1

Solution: Here,u=−2fv=?v1+u1=f1v1+−2f1=f1

 Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3

Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32f

 Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32fNow,

Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32fNow,M=u−v

Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32fNow,M=u−v=−(−2f)32f

Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32fNow,M=u−v=−(−2f)32f=31

Here,u=−2fv=?v1+u1=f1v1+−2f1=f1v1=2f3v=32fNow,M=u−v=−(−2f)32f=31(M is positive for convex mirror)

Hope it helps u....please mark mee as Brainiest.....