Question

for a conical pendulum of string length L, its angular speed is proportional to​

Answer 1

Answer:

Angular speed of the conical pendulum is given as

$\omega = \sqrt{\frac{g}{Lcos\theta}}$

Explanation:

As we know that the conical pendulum is revolving in circle in horizontal plane and its length is L making an angle "theta" with the vertical

so we will have

$Tcos\theta = mg$

$T sin\theta = m\omega^2 (L sin\theta)$

so we have

$\frac{mg}{cos\theta} = m\omega^2 L$

$\omega^2 = \frac{g}{Lcos\theta}$

so angular speed is given as

$\omega = \sqrt{\frac{g}{Lcos\theta}}$

#Learn

Topic : Conical pendulum

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