For a continuous random variable X whose probability density function is:
fx= {x for 0≤x<1 2-x for 1≤x<2 0 for x≥2
Calculate the cumulative distribution function F(x).
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Answered by
0
Answer:
To find c, we can use ∫∞−∞fX(u)du=1:
1 =∫∞−∞fX(u)du
=∫1−1cu2du
=23c.
Thus, we must have c=32.
To find EX, we can write
EX =∫1−1ufX(u)du
=32∫1−1u3du
=0.
In fact, we could have guessed EX=0 because the PDF is symmetric around x=0. To find Var(X), we have
Var(X) =EX2−(EX)2=EX2
=∫1−1u2fX(u)du
=32∫1−1u4du
=35.
To find P(X≥12), we can write
P(X≥12)=32∫112x2dx=716.
Answered by
0
Step-by-step explanation:
=2(
sin20
∘
3
/2
−
cos20
∘
1/2
)
=2(
sin20
∘
sin60
∘
−
cos20
∘
cos60
∘
)
=2(
sin20
∘
cos20
∘
sin60
∘
cos20
∘
−cos60
∘
sin20
∘
)
=2(
sin20
∘
cos20
∘
sin(60
∘
−20
∘
)
)
=2
sin20
∘
cos20
∘
sin40
∘
=2×
sin20
∘
cos20
∘
2sin20
∘
cos20
∘
=4
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