Question

For a d electron the orbital. Angular momentum is

Answer 1

Root 6h upon 2pie is the angular momentum for d electron

Answer 2

For, d orbital...l= 2
Orbital angular momentum = root of l(l+1) × h/2π
Therefore,
For d orbital .. angular momentum = √2(2+1) × 6.625 × 10^-34/2(3.14)
~ 25.5 × 10^-34