Question

For a damped harmonic oscillator, the equation of motion is0)/()/(22=+γ+kxdtdxdtxdmwithm= 0.50 kg,γ= 0.70 kgs−1andk= 70 Nm−1. Calculate (i) the period of motion,(ii) number of oscillations in which its amplitudewill become half of its initial value,(iii) the number of oscillations in which its mechanical energy will drop to half of itsinitial value, (iv) its relaxation time, and (v) quality factor.

Answer 1

A damped harmonic oscillator:  Equation of motion :
   x = displacement,   t = time,    k = constant (like spring constant)
   ¥ = damping factor (drag coefficient) = 0.70 N/m,
   m = mass of particle executing Periodic/oscillations = 0.50 kg
   The value of k is missing...  Let us assume k = 70 N/m

   m d²x/dt²  + ¥  dx/dt  + k x = 0
   dx²/dt² + 1.40 dx/dt + 140 x = 0
           std form of ODE:  d²x/dt² + p(t) dx/dt + q(t) x = 0
 
   Using the method of solving Ordinary differential equations for second degree equations:
   Let  x(t) = u(t) v(t)
   p(t) = 1.40,  v(t) = exp(-0.70 t),  q(t) = 140
   Q(t) = v''(t) + p(t) v'(t) + q(t) v(t) = 140 exp(- 0.70 t)
   Normal form of ODE:   v(t) u''(t) + Q(t) u(t) = 0
                                        u''(t) +140 u(t) = 0
        This is the equation of motion for a SHM.
      ω² = 140, ω = 2√35 rad/s
      u(t) = A Sin ωt 

Solution :  x(t) = A exp(- 0.70 t) Cos ωt
    If we are given x(t=0), then we can know the value of A.

    Period = 2π/ω =π/√35  Sec = 0.531 sec
 
    Amplitude = A exp(- 0.70 t)
   Time duration for amplitude to be come 1/2 of initial value
         =>   exp(- 0.70 t) = 1/2  
         =>  t = Ln 2 / 0.70 = 0.99 sec
    Number of oscillations = 0.99 /0.531 = 1.86 

  mechanical energy of the oscillator 
     = 1/2 k A² = 1/2 * 70 * A² * exp(- 1.40 t)
  It becomes half in t =  Ln 2 /1.40 = 0.495 sec
      ie., in 0.93 oscillations.

Relaxation time period of a damped oscillator is the time duration for its amplitude become 1/e of its initial value:
      So relaxation time =>   0.70 t = 1,   t = 1.43 sec

Quality factor = Energy stored in the oscillator / Energy lost during one oscillation
           = energy stored in the oscillator /energy lost during one radian of oscillation
 Q = ω/p(t) = 2√35 / 1.40 = 8.45

Here  p(t) = gamma is less than  2 ω.  So it is underdamping.