Physics, asked by bandnasingh3465, 6 months ago

For a de shunt motor of 5 kW, running at
1000 rpm, the induced torque will be:

Answers

Answered by Anonymous

Answer:

Torque = Power/(speed in rev/s)

= 5000/(2*pi*1000/60)

= 47.76 N.

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slove this question.

For a de shunt motor of 5 kW, running at1000 rpm, the induced torque will be:​

Answers

For a de shunt motor of 5 kW, running at
1000 rpm, the induced torque will be: