Question

for a dense flint glass prism of refracting angle 10° find angular deviation for extreme colors and dispersive power of dense flint glass.​

Answer 1

Answer:

The angular deviation for extreme colours are $7.92$ and $7.12$ and the dispersive power is $0.106$

Explanation:

Given refracting angle of the prism

$A=10^\circ$

$\mu_r=1.712$

$\mu_v=1.792$

Angle of deviation for red colour

$\delta_r=(\mu_r-1)A$

$\implies \delta_r=(1.712-1)\times 10$

$\implies \delta_r=7.12$

Angle of deviation for violet colour

$\delta_v=(\mu_v-1)A$

$\implies \delta_v=(1.792-1)\times 10$

$\implies \delta_v=7.92$

Angle of deviation for yellow colour (mean deviation)

$\delta_y=\frac{\delta_r+\delta_v}{2}$

$\implies \delta_y=\frac{7.12+7.92}{2}$

$\implies \delta_y=7.52$

The angle of deviation of the prism is given by

$\boxed{\omega=\frac{\delta_v-\delta_r}{\delta_y}}$

$\implies \omega=\frac{7.92-7.12}{7.52}$

$\implies \omega=0.106$

Therefore, the angular deviation for extreme colours are $7.92$ and $7.12$ and the dispersive power is $0.106$

Hope this helps.

Answer 2

Explanation:

The angular deviation for extreme colours are 7.927.92 and 7.127.12 and the dispersive power is 0.1060.106

Explanation:

Given refracting angle of the prism

A=10^\circA=10

∘

\mu_r=1.712μ

r

=1.712

\mu_v=1.792μ

v

=1.792

Angle of deviation for red colour

\delta_r=(\mu_r-1)Aδ

r

=(μ

r

−1)A

\implies \delta_r=(1.712-1)\times 10⟹δ

r

=(1.712−1)×10

\implies \delta_r=7.12⟹δ

r

=7.12

Angle of deviation for violet colour

\delta_v=(\mu_v-1)Aδ

v

=(μ

v

−1)A

\implies \delta_v=(1.792-1)\times 10⟹δ

v

=(1.792−1)×10

\implies \delta_v=7.92⟹δ

v

=7.92

Angle of deviation for yellow colour (mean deviation)

\delta_y=\frac{\delta_r+\delta_v}{2}δ

y

=

2

δ

r

+δ

v

\implies \delta_y=\frac{7.12+7.92}{2}⟹δ

y

=

2

7.12+7.92

\implies \delta_y=7.52⟹δ

y

=7.52

The angle of deviation of the prism is given by

\boxed{\omega=\frac{\delta_v-\delta_r}{\delta_y}}

ω=

δ

y

δ

v

−δ

r

\implies \omega=\frac{7.92-7.12}{7.52}⟹ω=

7.52

7.92−7.12

\implies \omega=0.106⟹ω=0.106

Therefore, the angular deviation for extreme colours are 7.927.92 and 7.127.12 and the dispersive power is 0.1060.106

Hope this helps.