Physics, asked by shriraminstitut5541, 1 year ago

For a equilibrium shown. the strings are strong enough to withstand a maximum tension of 100 n. what is the largest value of w they can support

Answers

Answered by dharaj22pch5o4
47

Hope this helps!!!The answer is 35 N.

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Answered by phillipinestest
19

First let us draw the free body diagram for showing the forces acting along the strings for withstanding a maximum tension of 100 N

                                        A.sin37 = B.sin53 ---(1)

To get the value of sin37 and sin 53, we need to remember one fact

In a right angle whose sides are of lengths 3, 4, 5 or are of lengths 6, 8, 10, the angles other than 90 degrees are 37^o and 53^o

So,

                 sin37^{o} = 3/5 = cos53^{o}\\sin53^{o} = 4/5 = cos37^{o}\\tan37^{o} = 3/4 = cot53^{o}\\tan53^{o} = 4/3 = cot37^{o}

Thus, Substituting the values in (1), we get

                  A\times 3/5 = B\times 4/5

                        3A = 4B

From this equation, we can clearly conclude that A > B

And as it is given that the maximum tension is 100 N  

                        A = 100N

So, B = 3/4\times 100 = 75 N

Substituting the values  

         A cos37 = W + B cos53

         100\times \frac {4} {5} = W + 75 \frac {3} {5}

We get  

80 = W + 45

W = 35 N

The largest W that the strings can support is 35N .

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