Question

For a first order gas phase reaction:

Answer 1

Answer:

Yes

Explanation:

because the gas in the centre of the breaker and heat the breaker

Answer 2

Answer:

For a first order gas phase reaction:  A2B2 → 2A(g) + 2B(g) at the temperature 400°C has the rate constant k = 2.0 x 10-4 sec-1. It is given that Antilog 0.0781 = 1.1971. K = 2.303/t * log a/(a-x). or, 2 * 10^(-4) = 2.303/900 * log 100/ (100 – x). Hence, x = 19.7 / 1.197 = 16.45% which is the percentage of A2B2 is decomposed on heating for 900 seconds.