Question

For a first order reaction : AⓇ 3B + 2C, with initial concentration 2M of A, it is 20% completed in
50 min. If initial concentration of A=10M, then find the concentration of B after 50 min.​

Answer 1

Answer:

Correct option is

C

62.13 min

Using integrated rate law expression.

Kt=ln

[A]

t

[A]

0

⇒20k=ln

0.8[A]

t

[A]

0

⇒k=(

20

1

)[ln10−3ln2]

Now,

t

1/2

is given by

k

0.693

⇒t

1/2

=

ln10−3ln2

0.693×20

=62.15min.