Question

For a first order reaction, show that the time
required for 99% completion is twice the time
required for the completion of 90% of reaction​

Answer 1

Explanation:

For a first order reaction, the time required for 99% completionis

t1 = 2.303/k Log 100/100-99

= 2.303/k Log 100

= 2x 2.303/k

For a first order reaction, the time required for 90% completion is

t2 = 2.303/k Log 100/100-90

= 2.303/k Log 10

= 2.303/k

Therefore, t1 = 2t2

Hence, the time required for 99% completion of a first order reaction is twice the time required for the completion of 90% of the reaction