Question

For a first order reaction, show that the time required for 99% completion of a first order reaction is twice the time required for the completion of 90%.

Answer 1

Answer: 2

Explanation:

T99%  = log(100)/(100-99)               Log100

____      _______________      =     ______

T90%  = log(100)/(100-90)               Log10

Answer 2

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