Question

For a first order reaction , tₐᵥ (average life time ) , t₅₀_% and t₇₅_% are in a order : * 1 point (A) t₅₀ < tₐᵥ < t₇₅ (B) t₅₀ < t₇₅< tₐᵥ (C) tₐᵥ​

Answer 1

Answer:

Correct option is

A

T

50

<T

av

<T

75

For first order reaction

T

50

=

k

0.693

T

av

=1.44×T

50

T

75

=

k

2.303

log

100−75

100

⟹

k

2.303

log4

⟹

k

2×0.693

=2×T

50

Hence T

50

<T

av

<T

75