Question

For a first. order. reaction velocity.constant. k=10-3 sec-1 two third. life. for. it. would. be

Answer 1

For a first order chemical reaction the the two third life would be equal to  

Explanation:

Given,

• The rate constant of the chemical reaction is equal to $10^{-3} sec^{-1}$
• Lets consider the initial amount of the  substrate B equal to a
• after two third of the chemical reaction the amount of substrate =, a-2/3a= a/3

The time taken for two third life is equal to, $\frac{2.303 log \frac{a}{a/3} }{k}$

• = $\frac{2.303 }{10^{-3}x 10^{-14} }$ , calculating the logarithm of the above values
• =2 x 10¹¹ sec

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