For a fixed beam, if it has a roller support at one end that is inclined at an angle 30° with the horizontal, what direction (angle) will the vertical reaction of that roller support act?
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Answer:
Given :
Length of beam = 9 m
Rate of U.D.L. = 10kN/m
Length of U.D.L. = 6 m
Total load due to U.D.L.
= (Length of U.D.L.) × Rate of U.D.L.
= 6 × 10 = 60 kN
The load of 60 kN will be acting at the middle point of AC i.e., at a distance of 3 m from A.
Let. RA = Reaction at A and RB = Reaction at B
Taking the moments of all forces about point A, and equating the resultant moment to zero, we get
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