Physics, asked by abhiudyaprakash, 1 month ago

For a floating body, how is its weight related to the buoyant force ? ​

Answers

Answered by shrestaBharath
0

Answer:

An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object.

Explanation:

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Answered by seenmp1975
0

Answer:

An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object

Explanation:

In general terms, this buoyancy force can be calculated with the equation Fb = Vs × D × g, where Fb is the buoyancy force that is acting on the object, Vs is the submerged volume of the object, D is the density of the fluid the object is submerged in, and g is the force of gravity

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